This can be done by calculating the average of two slopes.
Approximating instantaneous rate of change word problem:
Tuesday, October 7, 2014
Sunday, October 5, 2014
Vertical distance of bouncing ball
It is a tricky problem from Khan Academy but seems to be worth looking at.
Since the ball travels up the same distance as it travels down (except for the first bounce), the total vertical motion is
After the first term, the expression we have is twice the sum of an infinite geometric series with first term a=5 and common ratio r=12 .
Vertical distance of bouncing ball:
Saturday, October 4, 2014
Friday, October 3, 2014
Visualizing derivatives
For a curved slope, the derivative may be a straight line that has a gradient.
For a straight line with a gradient, the derivative is a constant value not equal to 0.
Visualizing derivatives exercise: Exercise available at https://www.khanacademy.org/math/calculus/differential-calculus/derivative_intro/e/visualizing_derivatives
Exercise made by Stephanie Chang
For a straight line with a gradient, the derivative is a constant value not equal to 0.
Visualizing derivatives exercise: Exercise available at https://www.khanacademy.org/math/calculus/differential-calculus/derivative_intro/e/visualizing_derivatives
Exercise made by Stephanie Chang
Monday, September 29, 2014
Range of a function
Saturday, September 27, 2014
Extreme value theorem
Thursday, September 25, 2014
How many ways can the letters in the word mathematics be arranged?
11!/(2!2!2!)=11!/8=4989600
Divide by two factorial for each of the three letters which appear twice: m,a,t.
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