From http://www.electronics-tutorials.ws/filter/filter_6.html
Introduction
A high pass filter will allow the frequencies which are higher than the cut-off frequency and attenuate the frequencies lower than the cut off frequency. In some cases this filter is also termed as ‘Low-Cut’ filter or ‘Base-cut’ filter. The amount of attenuation or the pass band range will depend on the designing parameters of the filter.
The pass band gain of an active filter is more than unity gain. The operation of the active high pass filter is same as passive high pass filter, but the main difference is that the active high pass filter uses an operational amplifier which provides amplification of the output signals and controls gain.The ideal characteristics of the high pass filter are shown below
Technically, there is no such thing as an active high pass filter. Unlike Passive High Pass Filters which have an “infinite” frequency response, the maximum pass band frequency response of an active high pass filter is limited by the open-loop characteristics or bandwidth of the operational amplifier being used, making them appear as if they are band pass filters with a high frequency cut-off determined by the selection of op-amp and gain.
Active High Pass Filter
By connecting a passive RC high pass filter circuit to the inverting or non-inverting terminal of the op-amp gives us first order active high pass filter. The passive RC high pass filter circuit connected to the non-inverting terminal of the unity gain operational amplifier is shown below.
The gain Amax = 1 and cutoff frequency fc = 1/2πRC
Active High Pass Filter With High Voltage Gain
The operation is the same as that of the passive high pass filter, but the input signal is amplified by the amplifier at the output. The amount of amplification depends on the gain of the amplifier. The magnitude of the pass band gain is equal to 1 + (R3/R2). Where R3 is the feedback resistor in Ω (ohms) and R2 is the input resistor. The circuit of an active high pass filter with amplification is given below
Voltage Gain Of An Active High Pass Filter
Voltage Gain Av = Amax (f/fc) / √{1 + (f/fc)²}
Where f = operating frequency
fc = cut-off frequency
Amax = pass band gain of the filter = 1 + (R3/R2)
At low frequencies means when the operating frequency is less than the cut-off frequency, the voltage gain is less than the pass band gain Amax. At high frequencies means when the operating frequency is greater than the cut-off frequency, the voltage gain of the filter is equal to pass band gain. If operating frequency is equal to the cut-off frequency,then the voltage gain of the filter is equal to 0.707 Amax.
Voltage Gain in (dB)
The magnitude of the voltage gain is generally taken in decibels (dB):
Av(dB) = 20 log10 (Vout/Vin)
-3 dB = 20 log10 (0.707 * Vout/Vin)
The cut-off frequency which separates both pass band and stop band can be calculated using the formula
fc = 1 / (2πRC)
fc = 1 / (2πRC)
The phase shift of the active high pass filter is equal to that of the passive filter. It is equal to +45° at the cut-off frequency fc and this phase shift value is equated as
Ø = tan-1(1/2πfcRC)
Frequency Response Of Active High Pass Filter
The frequency response curve with respect to the amplifiers open loop gain is shown below.
In frequency response of the active high pass filter the maximum pass band frequency is limited by the bandwidth or the open loop characteristics of the operational amplifier. Due to this limitation the active high pass filter response will appears like a wide band filter response. By using this op-amp based active high pass filter we can achieve high accuracy with the use of low tolerance resistors and capacitors.
Active High Pass Filter using Inverting Operational Amplifier
We know that the active high pass filter can be designed by using either inverting terminal or the non-inverting terminal of an operational amplifier. Till now we saw the high pass filter circuit and response curves of the non-inverting active high pass filter. Now let us see the active high pass filter using inverting op-amp.
Gain derivation in Laplace form
Let us consider the inverting amplifier as shown below
The input impedance Z1 = 1/sC1
Where s = Laplace Variable
C1 = Capacitance
The currents flowing in the circuit are I1, I2 and Iin,
Where I1 = I2 and Iin = 0
Vin / Z1 = -Vout / R1
Vout / Vin = – R1 / Z1
Vout / Vin = – R1 / (1/sC1)
Vout / Vin = -sR1C1 = Gain
Bode-plot
To analyse the circuit frequency response this bode plot is used. It is nothing but a graph of the transfer function of linear, time variant versus frequency. This is plotted with the log frequency axis. It consists of mainly two plots; one is magnitude plot and the other is phase plot.
The magnitude plot will express the magnitude of the frequency response i.e., gain and the phase plot is used to express the response of the frequency shift.
The frequency response bode-plot according to the values which are tabulated above is given below:
The frequency response bode-plot according to the values which are tabulated above is given below:
According to the values calculated, at frequency 10 Hz the gain of the filter obtained in dB is -56.48. If we increase the value of frequency to 100 Hz the obtained gain is -36.48 dB and at frequency 500 Hz the gain of the filter is -22.51 dB, at frequency 1000 Hz gain in dB is -16.52.By this we can say that if frequency increases the gain of the filter increases at the rate of 20dB/decade.
Till the cut-off frequency 10 KHz the gain of the filter increases but after the cut-off frequency the gain reaches maximum value and it is constant.
Second Order High Pass Filter
Second order active high pass filter frequency response is exactly opposite to the second order active low pass filter response because this filter will attenuate the voltages below the cut-off frequency. The transfer function of the second order filter is given below
Vout(s) / Vin(s) = -Ks² / s² + (ω0/Q)s + ω0²
Where K = R1/R2 and ω0 = 1/CR
This is the general form of the second order high pass filter.
Second Order Active High Pass Filter Circuit
The designing procedure for the second order active filter is same as that of the first order filter because the only variation is in the roll-off. If the roll-off of the first order active high pass filter is 20dB/decade, then roll-off of the second order filter is 40 dB/ decade. It means the twice of the value of the first order filter. The circuit of second order filter is shown below
The gain of the filter is 1+ R1/R2 and the equation of the cut-off frequency is fc = 1/ 2π√R3R4C1C2
Higher Order High Pass Filters
By cascading first order filter with second order filter , we can obtain the third order filter. When we cascade two second order filters we can get the fourth order filter. Like this with the help of first order and second order filters we get the higher order filters.
Applications of active high pass filters
- These are used in the loud speakers to reduce the low level noise.
- Eliminates rumble distortions in audio applications so these are also called are treble boost filters.
- These are used in audio amplifiers to amplify the higher frequency signals.
- These are also used in equalisers.
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