I use a formula like the one below to solve the problem in Khan Academy https://www.khanacademy.org/math/precalculus/hyperbolic_trig_topic/hyperbolic_trig_intro/e/equation_of_a_hyperbola.
y1 is moved to the other side giving a value that has an opposite sign. Please take note- this is not a fixed formula but one that I derive on my own to solve the problem faster.
y=±(b/a)(x+x1)-y1The fixed ones are as follows:-
http://www.purplemath.com/modules/hyperbola.htm
http://laurashears.info/math122/unit4/conics/whyBoverAisAsymp.htm
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